Euler 006 rust Solution

Problem

The sum of the squares of the first ten natural numbers is,

\[1^2 + 2^2 + ... + 10^2 = 385\]

The square of the sum of the first ten natural numbers is,

\[(1 + 2 + ... + 10)^2 = 55^2 = 3025\]

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is: \(3025 − 385 = 2640\).

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Answer: 25164150

Solution

euler006.rs

pub fn sum_squares(size: u32) -> u32
{
    let mut sum_square = 0;
    let mut square_sum = 0;

    for i in 1..size + 1 {
        sum_square += i * i;
        square_sum += i;
    }

    return (square_sum * square_sum) - sum_square;
}

#[cfg(test)]
mod tests {
    use super::*;

    #[test]
    fn euler_006() {
        assert_eq!(sum_squares(100), 25_164_150);
    }
}

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Euler 006 rust Solution

Problem

Solution

See Also