Euler 001 Rust Solution

Problem

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Answer: 233168

Solution

euler001.rs

pub fn sum_natural_35(upper:u32) -> u32
{
  let mut sum = 0;
  for i in 1..upper {
    if 0 == i % 3 {
      sum += i;
    } else if 0 == i % 5 {
      sum += i;
    }
  }
  return sum;
}

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Euler 001 Rust Solution

Problem

Solution

See Also