Euler 001 ruby Solution

Problem

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Answer: 233168

Solution

euler001.rb

#!/usr/bin/env ruby
def euler001_solution
  sum = 0
  (0..999).each do |num|
    sum += num if (num % 3 == 0) || (num % 5 == 0)
  end
  sum
end

puts euler001_solution if __FILE__ == $PROGRAM_NAME

Euler 001 ruby Solution

Problem

Solution

See Also